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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    2 moles of \[{{N}_{2}}{{O}_{4(g)}}\] is kept in a closed container at 298 K and under 1 atm pressure. It is heated to 596 K when 20% by mass of \[{{N}_{2}}{{O}_{4(g)}}\]) decomposes to \[N{{O}_{2}}\]. The resulting pressure is

    A)  \[2.4atm\]           

    B)  \[1.2atm\]

    C)  \[4.8atm\]

    D)  \[2.8atm\]

    Correct Answer: A

    Solution :

    \[\begin{align}   & \begin{matrix}    {} & 2{{N}_{2}}{{O}_{4}}\xrightarrow[{}]{} & 4N{{O}_{2}}  \\    Initially & 2 & 0  \\    At\,596\,K & 2p & 4p  \\ \end{matrix} \\  & \begin{matrix}    Finally & 2-2p & 4p  \\ \end{matrix} \\ \end{align}\] Initially     As given,    \[2p=\frac{20\times 2}{100}\] \[2p=0.4\] \[\therefore \]    \[p=0.2\text{ }atm\] Resulting pressure \[(P)=2-2p+4p\] \[P=2+2p\] \[P=2+2(0.2)=2.4atm\]


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