CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    The percentage of p-character of the hybrid orbital in graphite and diamond are respectively:

    A) \[33\] and \[25\]      

    B) \[50\] and \[75\]

    C)  67 and \[75\]    

    D) \[33\] and \[75\]

    Correct Answer: C

    Solution :

    : In diamond, each carbon is \[s{{p}^{3}}\]hybridised while in graphite each carbon has \[s{{p}^{2}}\]hybridisation. In \[s{{p}^{3}}\]-character \[\to \frac{3}{4}\times 100=75%\] In \[s{{p}^{2}}\] p-character \[\to \frac{2}{3}\times 100=66.6-67%\]


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