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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    A gas expands from a volume of \[1{{m}^{3}}\]to a volume of \[2{{m}^{3}}\]against an external pressure of \[{{10}^{5}}\text{ }N\text{ }{{m}^{-2}}\] The work done by the gas will be

    A) \[{{10}^{5}}kJ\]

    B) \[{{10}^{2}}kJ\]

    C) \[{{10}^{2}}J\]            

    D) \[{{10}^{3}}J\]

    Correct Answer: B

    Solution :

    : Work done \[(\omega )=P\Delta V\] \[=P\times ({{V}_{2}}-{{V}_{1}})\] \[={{10}^{5}}\times (2-1)\] \[\Rightarrow \] \[{{10}^{5}}J\] or \[{{10}^{2}}kJ\]


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