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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    An oxygen containing organic compound was found to contain 52% carbon and 13% of hydrogen. Its vapour density is 23. The compound reacts with sodium metal to liberate hydrogen. A functional isomer of this compound is

    A)  Ethanol         

    B)  Ethanal

    C)  Methoxy methane

    D)  Methoxy ethane

    Correct Answer: C

    Solution :

    : Molecular mass \[=2\times \] vapour density Molecular mass \[=2\times 23=46\]
    Element Percentage Atomic mass   Relative  number of   atoms Simplest ratio
    C 52% 12 \[52/12=4.33\] \[1.9-2\]
    H 13% 1 \[13/1=13\] \[5.9-6\]
    O 35% 16 \[35/16=2.18\] \[1\]
    Empirical formula \[={{C}_{2}}{{H}_{6}}O\] Empirical formula mass: \[=12\times 2+6\times 1+16=46\] \[n=\frac{empirical\,formula\,mass}{molecular\,formula\,mass}=\frac{46}{46}=1\] Molecular formula \[={{C}_{2}}{{H}_{6}}O\] Alcohols liberate hydrogen on reaction with sodium metal. The functional isomer of ethanol is methoxy methane. \[\underset{ethanol}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\] \[\underset{methoxy\,methane}{\mathop{C{{H}_{3}}OC{{H}_{3}}}}\,\]


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