A) \[112mL\]
B) \[56mL\]
C) \[224mL\]
D) \[560mL\]
Correct Answer: A
Solution :
: \[C{{H}_{3}}COOH+NaOH\xrightarrow{{}}C{{H}_{3}}COONa\] \[2C{{H}_{3}}COONa+2{{H}_{2}}O\xrightarrow{{}}\] \[C{{H}_{3}}-C{{H}_{3}}+2C{{O}_{2}}+2NaOH+{{H}_{2}}\] Number of moles of acetic acid = Number of moles of sodium acetate \[=0.1\times 100=10\]mmoles\[=10\times {{10}^{-3}}\] moles 2 moles of \[C{{H}_{3}}COONa\] on electrolysis produces \[22400mL\]of ethane. \[\therefore \]\[10\times {{10}^{-3}}\]moles of \[C{{H}_{3}}COONa\] will produce \[=\frac{22400\times 10\times {{10}^{-3}}}{2}=112mL\] of ethane.
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