A) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]
B) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
C) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
D) \[C{{H}_{2}}O\]
Correct Answer: A
Solution :
: Empirical formula mass, \[C{{H}_{2}}O=30\] \[n=\frac{Mol.\,mass}{Empirical\,formula\,mass}=\frac{90}{30}=3\] Molecular formula \[={{(Empirical\text{ }formula)}_{n}}\] \[={{(C{{H}_{2}}O)}_{3}}={{C}_{3}}{{H}_{6}}{{O}_{3}}\]
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