A) \[[Ar]\,3{{d}^{8}}\,4{{s}^{1}}\]
B) \[[Ar]\,3{{d}^{9}}\,4{{s}^{0}}\]
C) \[[Ar]\,3{{d}^{7}}\,4{{s}^{2}}\]
D) \[[Ar]\,3{{d}^{8}}\,4{{s}^{0}}\]
Correct Answer: B
Solution :
: \[_{29}Cu=[Ar]3{{d}^{10}}\,4{{s}^{1}}\] \[\therefore \] \[C{{u}^{2+}}=[Ar]3{{d}^{9}}4{{s}^{0}}\]
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