A) \[1.5\times {{10}^{3}}N{{C}^{-1}}\]
B) \[2\times {{10}^{3}}N{{C}^{-1}}\]
C) \[8\times {{10}^{3}}N{{C}^{-1}}\]
D) \[1.33\times {{10}^{3}}N{{C}^{-1}}\]
Correct Answer: C
Solution :
: As the charged particle passes unelected through cross electric and magnetic fields \[\therefore \] \[qE=q\upsilon B,\,\upsilon =\frac{E}{B}\] or \[E=\upsilon B\] Here, \[\upsilon =2\times {{10}^{3}}m{{s}^{-1}},\,\,B=1.5T\] \[\therefore \] \[E=(2\times {{10}^{3}}m{{s}^{-1}})(1.5T)=3\times {{10}^{3}}N{{C}^{-1}}\]
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