CET Karnataka Medical CET - Karnataka Medical Solved Paper-2013

  • question_answer
    Light emitted during the de excitation of electron from \[n=3\] to \[n=2\], when incident on a metal, photoelectrons are just emitted from that metal. In which of the following dexcitations photoelectric effect is not possible?

    A)  From \[n=2\] to \[n=1\]

    B)  From \[n=3\] to \[n=1\]

    C)  From \[n=5\] to \[n=2\]

    D)  From \[n=4\] to \[n=3\]

    Correct Answer: D

    Solution :

    : According to Bohrs theory energy of the electron in nth state is \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV\] \[\therefore \] \[{{E}_{1}}=\frac{-13.6}{{{3}^{2}}}=-13.6V\] \[{{E}_{2}}=\frac{-13.6}{{{2}^{2}}}=-3.4eV\] \[{{E}_{3}}=\frac{-13.6}{{{3}^{2}}}=-1.5eV\]\[{{E}_{4}}=\frac{-13.6}{{{4}^{2}}}=-0.85eV\] \[{{E}_{5}}=\frac{-13.6}{{{5}^{2}}}=-0.54eV\] For photoelectric effect energy should be more than \[{{E}_{3}}-{{E}_{2}}=-1.5eV-(-3.4eV)=1.9eV\] It is not possible in option \[\therefore \]  \[{{E}_{4}}-{{E}_{3}}=-0.85eV-(-1.5eV)=0.65eV\] It is possible in all other options.


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