question_answer

  

____________ \[3E\]

____________ \[5E/3\]

____________ \[E\]

The figure shows the energy level of certain atom. When the electron deexcites from \[3E\] to\[E\], an electromagnetic wave of wavelength \[\lambda \] is emitted. What is the wavelength of the electromagnetic wave emitted when the electron de excites from \[\frac{5E}{3}\]to E?

A)  \[3\lambda \]      

B)  \[2\lambda \]    

C)  \[5\lambda \]    

D)  \[\frac{3\lambda }{5}\]

Correct Answer: A

Solution :

: From figure, \[\frac{hc}{\lambda }=3E-E=2E\]           ??.(i) \[\frac{hc}{\lambda }=\frac{5E}{3}-E=\frac{2}{3}E\]         ??.(ii) Divide (i) by (ii), we get \[\frac{\lambda }{\lambda }=3\] or  \[\lambda =3\lambda \]