A) 0.3 second
B) 0.2 second
C) 0.16 second
D) 0.4 second
Correct Answer: D
Solution :
: Time taken by the ball to reach the floor of the lift is \[t=\sqrt{\frac{2h}{a+g}}\] Here, \[h=1.25m,g=10m{{s}^{-2}},a=5m{{s}^{-2}}\] \[\therefore \] \[t=\sqrt{\frac{2\times 1.25m}{(5+10)m\,{{s}^{-2}}}}=0.4s\]
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