CET Karnataka Medical CET - Karnataka Medical Solved Paper-2013

  • question_answer
    For which combination of working temperatures of source and sink, the efficiency of Carnots heat engine is maximum?

    A)  \[600K,400K\]

    B)  \[400K,200K\]

    C)  \[500K,300K\]

    D)  \[300K,100K\]

    Correct Answer: D

    Solution :

    : Efficiency of Carnots engine, \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\] where \[{{T}_{1}}\] and \[{{T}_{2}}\] be the temperatures of source and sink respectively. In all four cases, \[{{T}_{1}}-{{T}_{2}}=200K\]. Therefore, 11 is maximum when 7i is minimum.


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