A) \[HPO_{4}^{-}\]
B) \[HPO_{4}^{2-}\]
C) \[{{H}_{3}}P{{O}_{4}}\]
D) \[PO_{4}^{3-}\]
Correct Answer: B
Solution :
: \[{{H}_{2}}PO_{4}^{-}\xrightarrow[_{-}{{H}^{+}}]{}HPO_{4}^{2-}\]
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