A) \[\Delta H\] is \[+ve\] and \[\Delta S\] is -\[-ve\]
B) \[\Delta H\] is \[-ve\] and \[\Delta S\] is \[+ve\]
C) \[\Delta H\] is \[+ve\] and \[\Delta S\] is +\[+ve\]
D) \[\Delta H\] is \[+ve\] and \[\Delta S\] is equal to zero.
Correct Answer: B
Solution :
: \[\Delta G=\Delta H-T\Delta S\](Gibbs energy equation) When, \[\Delta H\] is \[-ve\], but \[T\Delta S\] is \[+ve\xrightarrow{{}}\Delta G\] will be \[(-ve)\] [Highly spontaneous].
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