CET Karnataka Medical CET - Karnataka Medical Solved Paper-2013

  • question_answer
    Glucose when reduced with HI and red phosphorus gives

    A)  n-hexane       

    B)  n-heptane

    C)  n-pentane        

    D)  n-octane.

    Correct Answer: A

    Solution :

    : \[\underset{\text{Glucose}}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\xrightarrow[373K]{Hi/\operatorname{Re}d\,P}\]-hexane + 2-iodohexane


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