A) \[0.79:1\]
B) \[0.69:1\]
C) \[0.86:1\]
D) \[0.96:1\]
Correct Answer: B
Solution :
: Given information, the enthalpy of combustion of \[C{{O}_{2}}\]is wrong, it should be enthalpy of combustion of C. 1 kg of coke \[=\frac{1000}{12}=83.33moles\] \[C+{{O}_{2}}\xrightarrow{{}}\underset{83.33\times 395.5kJ}{\mathop{C{{O}_{2}}}}\,\] \[\underbrace{CO+{{H}_{2}}}_{Water\,gas}+{{O}_{2}}\xrightarrow{{}}\underset{83.33\times 570kJ}{\mathop{\underset{83.33\times (285+285)}{\mathop{C{{O}_{2}}+{{H}_{2}}O}}\,}}\,\] Now, the ratio of| coke | water gas | |
| \[83.33\times 393.5\] | : | \[83.33\times 570\] |
| \[\Rightarrow \] \[393.5\] | : | \[570\] |
| \[\Rightarrow \]\[0.69\] | : | \[1\] |
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