A) \[15m\]
B) \[30m\]
C) \[10m\]
D) \[22.5m\]
Correct Answer: D
Solution :
: Maximum height reached by the stone is \[{{H}_{\max }}=\frac{{{u}^{2}}\,{{\sin }^{2}}\theta }{2g}\] Here, \[u=30m\,{{s}^{-1}},\,\theta ={{45}^{o}},\,g=10\,m\,{{s}^{-2}}\] \[\therefore \] \[{{H}_{\max }}=\frac{{{(30)}^{2}}{{\sin }^{2}}{{45}^{o}}}{2\times 10}=\frac{30\times 30\times {{\left( \frac{1}{\sqrt{2}} \right)}^{2}}}{2\times 10}\] \[=\frac{45}{2}=22.5m\]
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