CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    A gyromagnetic ratio of the electron revolving in a circular orbit of hydrogen atom is\[8.8\times {{10}^{10}}C\text{ }k{{g}^{-1}}\]. What is the mass of the electron? Given charge of the electron \[=1.6\times {{10}^{-19}}C\].

    A)  \[1.1\times {{10}^{-29}}kg\]

    B)  \[1\times {{10}^{-29}}kg\]

    C)  \[\frac{1}{11}\times {{10}^{-29}}kg\]  

    D)  \[0.1\times {{10}^{-29}}kg\]

    Correct Answer: C

    Solution :

    : Gyromagnetic ratio of an electron \[=\frac{e}{2{{m}_{e}}}\] \[=8.8\times {{10}^{10}}C\,k{{g}^{-1}}\] \[\therefore \] Mass of the electron, \[{{m}_{c}}=\frac{e}{2\times 8.8\times {{10}^{10}}C\,k{{g}^{-1}}}=\frac{1.6\times {{10}^{19}}C}{2\times 8.8\times {{10}^{10}}C\,k{{g}^{-1}}}\]\[=0.0909\times {{10}^{-29}}kg\] \[=\frac{1}{11}\times {{10}^{-29}}kg\]


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