CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    A 10 kg metal block is attached to a spring of spring constant\[1000N\text{ }{{m}^{-1}}\]. A block is displaced from equilibrium position by 10 cm and released. The maximum acceleration of the block is

    A)  \[200m{{s}^{-2}}\]      

    B)  \[10m{{s}^{-2}}\]

    C)  \[0.1m\text{ }{{s}^{-2}}\]       

    D)  \[100m\text{ }{{s}^{-2}}\]

    Correct Answer: B

    Solution :

    : Here, Amplitude, \[A=10cm=0.1\text{ }m\] Spring constant, \[k=1000\text{ }N\text{ }{{m}^{-1}}\] Mass, \[m=10\text{ }kg\] Maximum acceleration of the block is \[{{a}_{\max }}={{\omega }^{2}}A=\frac{kA}{m}\] \[\left( \because \,\omega =\sqrt{\frac{k}{m}} \right)\] \[=\frac{1000N\,{{m}^{-1}}\times 0.1m}{10kg}=10\,m\,{{s}^{-2}}\]


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