CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    Diameter of the objective of a telescope is 200 cm. What is the resolving power of a telescope? Take wavelength of light =\[\text{5000}\overset{\text{o}}{\mathop{\text{A}}}\,\].

    A)  \[1\times {{10}^{6}}\]

    B)  \[6.56\times {{10}^{6}}\]

    C)  \[3.28\times {{10}^{6}}\]

    D)  \[3.28\times {{10}^{5}}\]

    Correct Answer: C

    Solution :

    : Here, Diameter of the objective, \[D=200cm=200\times {{10}^{-2}}m=2m\] Wavelength of light, \[\lambda =5000\overset{\text{o}}{\mathop{\text{A}}}\,=5000\times {{10}^{-10}}m=5\times {{10}^{-7}}m\] Resolving power of a telescope \[=\frac{D}{1.22\lambda }\] \[=\frac{2}{1.22\times 5\times {{10}^{-7}}}=\frac{4}{1.22}\times {{10}^{6}}=3.28\times {{10}^{6}}\]


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