CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    For Freundlich isotherm a graph of \[\log \frac{x}{m}\] is plotted against log P. The slope of the line and its y-axis intercept, respectively corresponds to

    A)  \[\frac{1}{n},k\]       

    B)  \[\log \frac{1}{n},k\]

    C)  \[\frac{1}{n},logk\]

    D)  \[\log \frac{1}{n},\,\log k\]

    Correct Answer: C

    Solution :

    : Mathematically, Freundlich adsorption isotherm can be written as, \[\underbrace{\log \frac{x}{m}}_{y}=\underbrace{\operatorname{logk}}_{c}+\underbrace{\log \frac{1}{n}}_{m}\underbrace{\log \,p}_{x}\]


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