A) Tetrachloridoaurate (III)
B) Tetrachloridoaurate (I)
C) Tetrachloridoaurate (II)
D) Dichloridoaurate (III).
Correct Answer: A
Solution :
: When gold dissolves in aqua regia, it gives tetrachloridoaurate(III) anion. \[2Au+3HN{{O}_{3}}+11HCl\to 2H[AuC{{l}_{4}}]\] \[+3NOCl+6{{H}_{2}}O\]
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