A) \[1\times {{10}^{-6}}\]
B) \[1\times {{10}^{-5}}\]
C) \[1\times {{10}^{-3}}\]
D) \[1\times {{10}^{-4}}\]
Correct Answer: C
Solution :
: Solubility of a gas \[\propto \] mole fraction \[^{n}{{N}_{2}}=\frac{5.5\times {{10}^{-3}}}{28}=1.96\times {{10}^{-4}}\] at 1 am Now, p \[\propto \] mole fraction then at 5 atm, the mole fraction will increase 5 times. Hence, \[5\times 1.96\times {{10}^{-4}}=9.8\times {{10}^{-4}}\] \[=10\times {{10}^{-4}}=1.0\times {{10}^{-3}}\]
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