A) \[C{{H}_{4}},S{{F}_{4}}\]
B) \[BC{{l}_{2}},Cl{{F}_{3}}\]
C) \[Xe{{F}_{2}},ZnC{{l}_{2}}\]
D) \[S{{O}_{2}},C{{O}_{2}}\]
Correct Answer: C
Solution :
: \[Xe{{F}_{2}}\]is linear in shape with 2 bond pairs and 3 lone pairs of electrons. \[ZnC{{l}_{2}}\] is also linear in shape with 2 bond pairs of electrons.
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