A) \[4\]
B) \[7\]
C) \[6\]
D) \[9\]
Correct Answer: C
Solution :
: \[_{1}H=1{{s}^{1}};{{\,}_{3}}Li=2{{s}^{1}};{{\,}_{11}}Na=3{{s}^{1}};{{\,}_{19}}K=[Ar]\] \[4{{s}^{1}}_{24}Cr=[Ar]3{{d}^{5}}\,4{{s}^{1}}{{\,}_{29}}Cu=[Ar]\,3{{d}^{10}}\,4{{s}^{1}}\]
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