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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    A crystalline solid X reacts with dil. \[HCl\] to liberate a gas Y. Y decolourises acidified \[KMn{{O}_{4}}\]. When a gas Z is slowly passed into an aqueous solution of Y, colloidal sulphur is obtained. X and Z could be, respectively

    A)   \[N{{a}_{2}}S,S{{O}_{3}}\]

    B)  \[N{{a}_{2}}S{{O}_{4}},{{H}_{2}}S\]

    C)  \[N{{a}_{2}}S{{O}_{3}},{{H}_{2}}S\]

    D)  \[N{{a}_{2}}S{{O}_{4}},S{{O}_{2}}\]

    Correct Answer: C

    Solution :

    : \[\underset{X}{\mathop{N{{a}_{2}}S{{O}_{3(s)}}}}\,+2HC{{l}_{(dil)}}\to 2NaCl+S{{O}_{2(g)}}\uparrow \]      \[+{{H}_{2}}O\] \[{{H}_{2}}O+S{{O}_{2(g)}}\to \underset{\begin{smallmatrix}  Sulphurous\,acid \\  (An\,aq.\,\,solution\,og\,Y) \end{smallmatrix}}{\mathop{{{H}_{2}}S{{O}_{3}}_{(aq)}}}\,\] \[{{H}_{2}}S{{O}_{3}}+\underset{Z}{\mathop{2{{H}_{2}}{{S}_{(g)}}}}\,\to \underset{(Colloidal)}{\mathop{3S}}\,+3{{H}_{2}}O\]


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