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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2015

  • question_answer
    In a first order reaction, the concentration of the reactant is reduced to 12.5% in one hour. When was it half completed?

    A)  \[20min\]          

    B)  \[15min\]

    C)  \[3hr\]            

    D)  \[30min\]

    Correct Answer: A

    Solution :

    : For a first order reaction: \[k=\frac{2.303}{t}\log \frac{{{[A]}_{0}}}{[A]}=\frac{2.303}{60}\log \frac{100}{12.5}=0.0346{{\min }^{-1}}\]Now   \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.0346}=20\min \]


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