A) 0.6% glucose solution
B) 0.1 M glucose solution
C) 0.06% glucose solution
D) 0.01 M glucose solution.
Correct Answer: D
Solution :
; Molarity of 0.06% (w/v) aqueous solution of urea \[=\frac{0.06\times 1000}{60\times 100}=0.01M\] As osmotic pressure \[(\pi )=CRT\] \[\therefore \] 0.01M solution of urea will be isotonic with 0.01M glucose solution.
You need to login to perform this action.
You will be redirected in
3 sec
