A) \[0.693\times 3M\text{ }mi{{n}^{-1}}\]
B) \[0.0693\times 4M\text{ }mi{{n}^{-1}}\]
C) \[0.0693M\text{ }mi{{n}^{-1}}\]
D) \[0.0693\times 3M\text{ }mi{{n}^{-1}}\]
Correct Answer: D
Solution :
: \[\underset{Initial\,conc.}{\mathop{12M}}\,\,\xrightarrow{{{t}_{1/2}}}6M\xrightarrow{{{t}_{1/2}}}3M\] \[{{t}_{1/2}}=10\min \] \[k=\frac{0.693}{10}=0.0693{{\min }^{-1}}\] As \[{{t}_{1/2}}\] is 10 min, after 20 minutes the concentration will be 3 M. Hence, Rate \[=0.0693\times 3\text{ }M\text{ }mi{{n}^{-1}}\]
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