A) \[V{{I}^{2}}\]
B) zero
C) \[\frac{1}{2}VI\]
D) \[\frac{V{{I}^{2}}}{4}\]
Correct Answer: B
Solution :
: The average power dissipated is \[{{P}_{av}}=VI\cos \phi \] where \[\cos \phi \] is the power factor. For pure inductor, \[\phi =\frac{\pi }{2}\] \[\therefore \] \[\cos \phi =0\] or \[{{P}_{sv}}=0\] Thus the average power dissipated in a pure inductor is zero.
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