CET Karnataka Medical CET - Karnataka Medical Solved Paper-2015

  • question_answer
    A radioactive decay can form an isotope of the original nucleus with the emission of particles

    A)  One \[\alpha \] and two \[\beta \]

    B)  Four \[\alpha \] and one \[\beta \]

    C)  One \[\alpha \]and four \[\beta \]

    D)  One \[\alpha \] and one \[\beta \]

    Correct Answer: A

    Solution :

    : As the emission of an alpha particle decreases the atomic number and mass number by 2 and 4 respectively while the emission of a beta particle increases the atomic number by 1 but mass number remains the same. So, the emission of one alpha particle and two beta particles from the nucleus can form an isotope of the original nucleus. It may be represented as \[_{Z}{{X}^{A}}{{\xrightarrow{\alpha }}_{Z-2}}{{Y}^{A-4}}{{\xrightarrow{2{{\beta }^{-}}}}_{Z}}{{X}^{A-4}}\]


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