A) \[\frac{RC}{25}\]
B) \[\frac{5RC}{36}\]
C) \[\frac{3RC}{27}\]
D) \[\frac{8RC}{9}\]
Correct Answer: B
Solution :
: When an electron jumps from higher level \[{{n}_{1}}\] to lower energy level \[{{n}_{2}}\], the frequency of the emitted radiation is \[\upsilon =RC\left[ \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right]\] \[\therefore \] For \[n=3\] to \[n=2\], \[\upsilon =RC\left[ \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right]=RC\left[ \frac{1}{4}-\frac{1}{9} \right]\] \[=RC\left[ \frac{9-4}{36} \right]=\frac{5RC}{36}\]
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