A) \[2.0A\]
B) \[1.33A\]
C) \[1.71\text{ }A\]
D) \[2.31A\]
Correct Answer: C
Solution :
: In the given circuit diode \[{{D}_{1}}\] is forward biased and \[{{D}_{2}}\] is reverse biased. The resistance of \[{{D}_{1}}\] is zero and that of \[{{D}_{2}}\] is in finite as the diodes \[{{D}_{1}}\] and \[{{D}_{2}}\]are ideal. No current flows through \[{{D}_{2}}\]. Thus \[{{D}_{1}}\]can be replaced by a resistance less wire and \[{{D}_{2}}\] can be replaced by a broken wire. The equivalent circuit is shown in the figure.
The current in the circuit is \[I=\frac{12V}{4\Omega +3\Omega }=\frac{12V}{7\Omega }=1.71A\]
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