CET Karnataka Medical CET - Karnataka Medical Solved Paper-2015

  • question_answer
    A particle is projected with a velocity v so that its horizontal range twice the greatest height attained. The horizontal range is

    A)  \[\frac{2{{V}^{2}}}{3g}\]

    B)  \[\frac{{{v}^{2}}}{2g}\]

    C)  \[\frac{{{v}^{2}}}{g}\]

    D)  \[\frac{4{{v}^{2}}}{5g}\]

    Correct Answer: C

    Solution :

     \[\frac{{{v}^{2}}}{g}\]


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