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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2015

  • question_answer
    A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

    A)  0.49 N vertically downwards

    B)  9.8 N vertically downwards

    C)  0.49 N vertically upwards

    D)  0.98 N vertically downwards

    Correct Answer: A

    Solution :

    : Here, Mass of the stone, \[m=0.05\text{ }kg\] The magnitude of net force on the stone is \[F=mg=(0.05kg)(9.8m\,{{s}^{-2}})=0.49N\] Its direction is vertically downwards.


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