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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2015

  • question_answer
    The efficiency of a Carnot engine which operates between the two temperatures \[{{T}_{1}}=500K\] and \[{{T}_{2}}=300K\] is

    A)  \[25%\]  

    B)  \[40%\]

    C)  \[50%\]  

    D)  \[75%\]

    Correct Answer: B

    Solution :

    : The efficiency of a Carnot engine is \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] Here, \[{{T}_{1}}=500K,\,\,{{T}_{2}}=300K\] \[\therefore \] \[\eta =1-\frac{300K}{500K}=\frac{500K-300K}{500K}\] \[=\frac{200K}{500K}=\frac{2}{5}=\frac{2}{5}\times 100%=40%\]


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