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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2015

  • question_answer
    Three resistances \[2\Omega \], \[3\Omega \]. and \[4\Omega \] are connected in parallel. The ratio of currents passing through them when a potential difference is applied across its ends will be

    A)  \[6:4:3\]           

    B)  \[4:3:2\]

    C)  \[6:3:2\]          

    D)  \[5:4:3\]

    Correct Answer: A

    Solution :

    : When resistances are connected in  parallel, \[I\propto \frac{1}{R}\] \[\therefore \] \[{{I}_{1}}:{{I}_{2}}:{{I}_{3}}=\frac{1}{{{R}_{1}}}:\frac{1}{{{R}_{2}}}:\frac{1}{{{R}_{3}}}\] \[=\frac{1}{2}:\frac{1}{3}:\frac{1}{4}=\frac{12}{2}:\frac{12}{3}:\frac{12}{4}=6:4:3\]


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