A) \[C{{H}_{3}}COC{{H}_{3}}\]and \[{{B}_{3}}{{N}_{3}}{{H}_{6}}\]
B) \[{{({{C}_{2}}{{H}_{5}})}_{2}}O\] and \[NaB{{H}_{4}}\]
C) \[{{C}_{2}}{{H}_{6}}\]and \[{{C}_{2}}{{H}_{5}}Na\]
D) \[{{C}_{6}}{{H}_{6}}\]and \[NaB{{H}_{4}}\]
Correct Answer: B
Solution :
: \[2NaH+{{B}_{2}}{{H}_{6}}\xrightarrow[A]{{{({{C}_{2}}{{H}_{5}})}_{2}}O}\underset{B}{\mathop{\underset{Sodium\,borohydride}{\mathop{2NaB{{H}_{4}}}}\,}}\,\]
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