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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    The coils of a step down transformer have 501 and 5000 turns. In the primary coil an AC of 4 A at 2200 V is sent. The value of the current and potential difference in secondary coil will be

    A)  20 A, 220V                         

    B)  0.4 A, 22000V

    C)  40 A, 220 V                        

    D)  40 A, 22000 V

    Correct Answer: C

    Solution :

    \[\frac{{{e}_{s}}}{{{e}_{p}}}=\frac{{{N}_{s}}}{{{N}_{p}}}\] Given, \[{{N}_{s}}=500,\]\[{{N}_{p}}=5000,\]\[{{e}_{p}}=2200V\] \[\therefore \]  \[{{e}_{s}}=\frac{{{N}_{s}}}{{{N}_{p}}}\times {{e}_{p}}\]                 \[=\frac{500}{5000}\times 2200=220V\] Again     \[\frac{{{e}_{s}}}{{{e}_{p}}}=\frac{{{I}_{p}}}{{{I}_{s}}}\] or            \[{{I}_{s}}=4\times \frac{2200}{220}=40A\]


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