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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2004

  • question_answer
    The order of a reaction with rate equal to  \[kC_{A}^{3/2}C_{B}^{-1/2},\] is

    A)  \[2\]                                    

    B)  \[1\]

    C)  \[-\frac{1}{2}\]                                

    D)  \[\frac{3}{2}\]          

    Correct Answer: B

    Solution :

    Given, rates \[=KC_{A}^{3/32}C_{B}^{-1/2}\] Order of reaction = Sum of power raised on concentration terms, So, order of reaction \[=\frac{3}{2}+\left( -\frac{1}{2} \right)\]                                                 \[=\frac{3-1}{2}=\frac{2}{2}=1\]


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