A) \[Z{{n}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Zn(s)\]
B) \[Zn(s)+2{{e}^{-}}\xrightarrow{{}}Zn(s)\]
C) \[M{{n}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Mn(s)\]
D) \[Mn(s)\xrightarrow{{}}M{{n}^{+}}+{{e}^{-}}1.5V\]
Correct Answer: B
Solution :
\[Zn(s)\xrightarrow{{}}Z{{n}^{2+}}+2{{e}^{-}}\]Because in dry cell at graphite anode (\[-ve\] electrode) oxidation occurs.
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