A) \[{{H}_{2}}O\]
B) \[{{H}_{2}}S\]
C) \[{{H}_{2}}Se\]
D) \[{{H}_{2}}Te\]
Correct Answer: B
Solution :
Boiling point of \[{{H}_{2}}O>\] Boiling point of \[{{H}_{2}}S\] or \[{{H}_{2}}O\] is liquid and \[{{H}_{2}}S\] is gas. The boiling point of covalent compound increases with increase b.p. but \[{{H}_{2}}O\] is liquid (high b.p) and \[{{H}_{2}}S\] is gas due to presence of H-bonding between \[{{H}_{2}}O\] molecules. Therefore, \[{{H}_{2}}S\] has lowest boiling point.
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