A) \[NiS{{O}_{4}}\]
B) \[Ba{{S}_{2}}{{O}_{3}}\]
C) \[Pb{{S}_{2}}{{O}_{3}}\]
D) \[CuS{{O}_{4}}\]
Correct Answer: B
Solution :
Since the salt on treatment with dil. \[HCl\] gives a pungent smelling gas and a yellow ppt, it contains \[{{S}_{2}}O_{3}^{2-}\]ion. \[{{S}_{2}}O_{3}^{2-}+2HCl\to \underset{\begin{smallmatrix} yellow \\ ppt. \end{smallmatrix}}{\mathop{S\downarrow }}\,+\underset{\begin{smallmatrix} Pungent \\ smelling \\ gas \end{smallmatrix}}{\mathop{S{{O}_{2}}\uparrow }}\,+{{H}_{2}}O+2C{{l}^{-}}\] As it gives green colour to flame, hence contains \[B{{a}^{2+}}\] ion. \[\therefore \]The salt is \[Ba{{S}_{2}}{{O}_{3}}\]. \[Ba{{S}_{2}}{{O}_{3}}+{{K}_{2}}Cr{{O}_{4}}\xrightarrow{{}}\underset{\begin{smallmatrix} yellow \\ ppt. \end{smallmatrix}}{\mathop{BaCr{{O}_{4}}}}\,+{{K}_{2}}{{S}_{2}}{{O}_{3}}\]
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