A) \[0.31\times {{10}^{-6}}\,\text{rad}\]
B) \[0.25\times {{10}^{-6}}\,\text{rad}\]
C) \[0.6\times {{10}^{-3}}\,\text{rad}\]
D) \[0.5\times {{10}^{-3}}\,\text{rad}\]
Correct Answer: A
Solution :
Resolving power of a telescope \[d\theta =\frac{1.22\lambda }{a},\]where a is diameter \[=\frac{1.22\times 5000\times {{10}^{-10}}}{2}\] \[=0.31\times {{10}^{-6}}rad\]
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