A) \[1.5\]
B) \[2.0\]
C) \[2.5\]
D) \[3.0\]
Correct Answer: C
Solution :
Total number of electron in \[NO=15\] Number of bonding electrons \[({{N}_{a}})=10\] No. of anti bonding electrons \[({{N}_{b}})=5\] Bond order \[=\frac{{{N}_{b}}-{{N}_{a}}}{2}\] Bond order \[=\frac{10-5}{2}=2.5\]
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