Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2005

  • question_answer
    What is Y in the following nuclear reaction? \[_{7}{{H}^{14}}{{+}_{1}}{{H}^{1}}{{\xrightarrow{{}}}_{8}}{{O}^{15}}+'X'\]

    A)  \[_{0}{{n}^{1}}\]                             

    B)  \[_{-1}{{e}^{0}}\]

    C)  \[_{+1}{{e}^{0}}\]                                          

    D)  Energy

    Correct Answer: D

    Solution :

    Suppose the unknown products is \[_{Z}{{X}^{M}}\]. Therefore, nuclear equation will be                 \[_{7}{{N}^{14}}{{+}_{1}}{{H}^{1}}{{\xrightarrow{{}}}_{8}}{{O}^{15}}{{+}_{Z}}{{X}^{M}}\] Putting the mass number of both sides equal \[14+1=15+M\] or \[M=0\] Putting the nuclear charge of both sides equal \[7+1=8+Z\]or \[Z=0\] So, above reaction is balanced, so X is energy.


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