A) \[{{K}_{2}}S\]
B) \[S\]
C) \[{{K}_{2}}S{{O}_{3}}\]
D) \[Mn{{O}_{2}}\]
Correct Answer: B
Solution :
Reduction of \[KMn{{O}_{4}}\]in acidic solution \[2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}+5{{H}_{2}}S\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}\] \[+2MnS{{O}_{4}}+8{{H}_{2}}O+5S\] So, by passing \[{{H}_{2}}S\] gas in acidified \[KMn{{O}_{4}}\] solution we get sulphur.
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