A) greater than the final pressure of B
B) equal to the final pressure of B
C) less than the final pressure of B
D) twice the final pressure of B
Correct Answer: C
Solution :
For sample \[A\to \] in isothermal process By Boyle's law \[{{p}_{1}}{{V}_{1}}={{p}_{2}}{{V}_{2}}\] \[\Rightarrow \] \[{{p}_{2}}=p\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)\] \[{{p}_{2}}=p\left( \frac{V}{V/2} \right)=2p\] For sample \[B\to \] in adiabatic process By Poisson's law \[pV_{1}^{\gamma }={{p}_{2}}V_{2}^{\gamma }\] \[\therefore \] \[{{p}_{2}}=p{{(2)}^{\gamma }}\] \[\because \] \[\gamma >1\] \[\therefore \] \[2\gamma >2\] \[\therefore \] \[2\gamma \,p>2p\] or \[{{({{p}_{2}})}_{B}}>{{({{p}_{2}})}_{A}}\] Final pressure of A is less than pressure of B.
You need to login to perform this action.
You will be redirected in
3 sec
