A) 0.026 MeV
B) 0.051 MeV
C) 0.079 MeV
D) 0.105 MeV
Correct Answer: C
Solution :
The relation between the rest energy and moving energy is \[E=\frac{{{E}_{0}}}{\sqrt{1-{{v}^{2}}/{{c}^{2}}}}\] \[\because \] \[v=0.5c\] \[\therefore \] \[E=\frac{{{E}_{0}}}{\sqrt{1-0.25}}\] \[=\frac{{{E}_{0}}}{\sqrt{0.75}}\] Change in energy \[\Delta \,E=E-{{E}_{0}}\] \[=\frac{{{E}_{0}}}{\sqrt{0.75}}-{{E}_{0}}\] \[={{E}_{0}}\left( \frac{1}{\sqrt{0.75}}-1 \right)\] \[=0.511\left( \frac{1}{\sqrt{0.75}}-1 \right)\] \[=0.079MeV\]
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