A) \[3\]
B) \[5\]
C) \[4\]
D) \[2\]
Correct Answer: A
Solution :
The dot structure of \[Xe{{F}_{2}}\] is as follows\[F-\mathbf{:}\underset{\bullet \bullet }{\overset{\bullet \bullet }{\mathop{Xe}}}\,-F\] Number of molecular hybrid orbitals = number of sigma bonds + number of lone pair of electrons. \[\therefore \] Number of molecular hybrid orbitals \[~=2+3=5\] So, hybridization is \[s{{p}^{3}}d\].
You need to login to perform this action.
You will be redirected in
3 sec
